solving differential equation for diffrent intial condition

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samee baig
samee baig am 14 Jul. 2016
Kommentiert: samee baig am 14 Jul. 2016
I am trying to solve differential equation for different initial conditions and plotting the result for each initial condition.i need help on writing a code using a loop to do the same and plotting the result against each initial condition. my current code is as below function xdot=fifteenstate2(t,x)
T=1;
v(1) =-x(1)-x(2)*x(3)-x(3)*x(4)-x(5)*x(6)-x(7)*x(8)-x(9)*x(10)-x(11)*x(12)-x(13)*x(14);
v(2) = -x(2);
v(3) =-x(5);
v(4) =-x(5)*x(6)-x(7);
v(5) =-x(9);
v(6) =-x(11);
v(7) =-x(13);
v(8) =x(3);
v(9) =x(6);
v(10) =x(8);
v(11) =x(10);
v(12) =x(12);
v(13) =x(14);
v(14) =x(4);
v=[v(1);v(2);v(3);v(4);v(5);v(6);v(7);v(8);v(9);v(10);v(11);v(12);v(13);v(14)];
%uu=[1;1;1;1;1;1;1];
d(1)=3.54491*sign(v(8))*sqrt(abs(v(8))/T);
d(2)=3.54491*sign(v(9))*sqrt(abs(v(9))/T);
d(3)=3.54491*sign(v(10))*sqrt(abs(v(10))/T);
d(4)=3.54491*sign(v(11))*sqrt(abs(v(11))/T);
d(5)=3.54491*sign(v(12))*sqrt(abs(v(12))/T);
d(6)=3.54491*sign(v(13))*sqrt(abs(v(13))/T);
d(7)=3.54491*sign(v(14))*sqrt(abs(v(14))/T);
d=[d(1);d(2);d(3);d(4);d(5);d(6);d(7)];
y(1)=sin((2*pi*t)/T); y(2)=cos((2*pi*t)/T);
y=[y(1);y(2)];
uu(1)=v(1)+d(1)*y(2)+d(2)*y(2)-d(3)*y(2)-d(4)*y(1)-d(5)*y(1)+d(6)*y(2);%+d(7)*y(1)+d(1)*d(7)*y(2)*y(2);
uu(2)=v(2)+d(1)*y(1);%-d(1)*d(7)*y(1)*y(2);
uu(3)=v(3)+d(2)*y(1);
uu(4)=v(4)+d(3)*y(1);
uu(5)=v(5)+d(4)*y(2);
uu(6)=v(6)+d(5)*y(2);
uu(7)=v(7)+d(6)*y(1);
uu=[uu(1);uu(2);uu(3);uu(4);uu(5);uu(6);uu(7)];
xdot(1)=uu(1); xdot(2)=uu(2); xdot(3)=x(2)*uu(1); xdot(4)=x(3)*uu(1); xdot(5)=uu(3); xdot(6)=x(5)*uu(1); xdot(7)=uu(4); xdot(8)=x(7)*uu(1); xdot(9)=uu(5); xdot(10)=x(9)*uu(1); xdot(11)=uu(6); xdot(12)=x(11)*uu(1); xdot(13)=uu(7); xdot(14)=x(13)*uu(1); xdot=xdot';
clear all close all clc
Tspan =linspace(0,100,500);
IC=[1;-3;2;-2;3;-4;1;-2;5;3;-2;-2;2;-3]; %options = odeset('RelTol',1e-2,'AbsTol',[1e-2 1e-2 1e-2 1e-2 1e-2 1e-2]); [T,Y] = ode45(@fifteenstate2, Tspan,IC)
x1 = Y(:,1); x2 = Y(:,2); x3 = Y(:,3); x4 = Y(:,4); x5 = Y(:,5); x6 = Y(:,6); x7 = Y(:,7); x8 = Y(:,8); x9 = Y(:,9); x10 = Y(:,10); x11 = Y(:,11); x12 = Y(:,12); x13 = Y(:,13); x14 = Y(:,14);
figure(1) plot(T,x1,T,x3,T,x4,T,x6,T,x8,T,x10,T,x12,T,x14,'linewidth',2) legend('x1','x3','x4','x6','x8','x10','x12','x14',8); xlabel('t(s)') ylabel('x_1,x_3,x_4,x_6,x_8,x_10,x_12,x_14') grid on
figure(2) plot(T,x2,T,x5,T,x7,T,x9,T,x11,T,x13,'linewidth',2) legend('x2','x5','x7','x9','x11','x13',6); xlabel('t(s)') ylabel('x_2,x_5,x_7,x_9,x_11,x_13') grid on
  2 Kommentare
KSSV
KSSV am 14 Jul. 2016
ok.....go ahead, do it.......is some thing objecting you?
samee baig
samee baig am 14 Jul. 2016
yes,cannot seem to figure out how to write the code

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Akzeptierte Antwort

Mischa Kim
Mischa Kim am 14 Jul. 2016
Samee, check out this answer. It does exactly what you are looking for.
  1 Kommentar
samee baig
samee baig am 14 Jul. 2016
its not working,is it because the initial condition i wrote are in vector form ?

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