split array

if A = [1234567891234567];===> size(A) = 1*1

in one cell

I want split it as each (8digit) in one cell as:

A = [12345678;91234567];=====> size(A)= 2*1

Answer 1

[Krishnendu Mukherjee]

for i=1:(size(A(1,:))/2) B(1,:)=A(1,i); end for i=(size(A(1,:))/2):size(A(1,:)) B(2,:)=A(1,i); end try this.it may work

[Aseel H]

error

??? Subscript indices must either be real

positive integers or logicals.

[Krishnendu Mukherjee]

for i=1:(size(A(1,:))/2) B(1,i)=A(1,i); end for i=(size(A(1,:))/2):size(A(1,:)) B(2,i)=A(1,i); end try this.it may work

1 comment

[Krishnendu Mukherjee]

i was in hurry yesterday.thats why little mistake

Answer 2

[Andrei Bobrov]

A = 1234567891234567
B = reshape(num2str(A)-'0',[],2).'
Anew = B*10.^(size(B,2)-1:-1:0).'

Answer 3

[Walter Roberson]

Your A is 16 digits long. You might not be able to store it accurately as a floating point number.