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How do you append to a matrix within a for loop?

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chels19
chels19 am 8 Jul. 2016
Kommentiert: Mani am 8 Mai 2024
Hi, I am using a for loop to process data (this part works fine). What I need to do is take the matrix (A) and after each loop update A to create one matrix. For instance, in the image below A is produced on the first loop, during loop 2 A "grows" to include the data from loop 1 and the data from loop 2, and so on.
Loop 1 produces a matrix, on the next iteration I need to append to this matrix the results of that loop, and so on until all of the data is processed.
It should be noted that the number of rows on each loop is unknown. However, the number of columns is fixed to 7.
Any ideas would be greatly appreciated please.

Akzeptierte Antwort

José-Luis
José-Luis am 8 Jul. 2016
Bearbeitet: José-Luis am 8 Jul. 2016
your_result = [];
for ii = whatever
some_vector = some_function(of_something);
your_result = [your_result; {some_vector}];
end
  8 Kommentare
Ruijie Zhu
Ruijie Zhu am 4 Okt. 2021
cheers mate
Mani
Mani am 8 Mai 2024
Nice one.

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Weitere Antworten (2)

Azzi Abdelmalek
Azzi Abdelmalek am 8 Jul. 2016
A=[1 2;3 4]
B=[4 5;6 7]
A=[A;B]
  1 Kommentar
chels19
chels19 am 8 Jul. 2016
Thank you but this just replaces the data within the loop. I need to update A on every iteration so that it grows.

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SRIAKILAN S A
SRIAKILAN S A am 21 Feb. 2023
% make an empty array
% the main command is end+1
N=[];
for i=0:10
x=i*i;
N(end+1)=[x]
end
N = 0
N = 1×2
0 1
N = 1×3
0 1 4
N = 1×4
0 1 4 9
N = 1×5
0 1 4 9 16
N = 1×6
0 1 4 9 16 25
N = 1×7
0 1 4 9 16 25 36
N = 1×8
0 1 4 9 16 25 36 49
N = 1×9
0 1 4 9 16 25 36 49 64
N = 1×10
0 1 4 9 16 25 36 49 64 81
N = 1×11
0 1 4 9 16 25 36 49 64 81 100

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