How to convert cell 2 mat?

This is my code:

data03=[];
l=length(strc201603{1});
data03=zeros(l,16);
for i=1:l
    data03(i,1)=day(strc201603{4}(i));
    data03(i,2)=month(strc201603{4}(i));
    data03(i,3)=year(strc201603{4}(i));
    data03(i,4)=hour(strc201603{13}(i))+minute(C_data0{13}(i))/60+second(C_data0{13}(i))/3600;
    data03(i,5)=hour(strc201603{14}(i))+minute(C_data0{14}(i))/60+second(C_data0{14}(i))/3600;
    data03(i,6)=hour(strc201603{15}(i))+minute(C_data0{15}(i))/60+second(C_data0{15}(i))/3600;
    data03(i,7)=hour(strc201603{16}(i))+minute(C_data0{16}(i))/60+second(C_data0{16}(i))/3600;
    data03(i,8)= strc201603{17}(i);
    data03(i,9)= strc201603{18}(i);
    a=char(strc201603{2}(i));
    a=strrep(a,'N','1');
    a=strrep(a,'P','2');
    a=str2num(a);
    data03(i,10)=a;
    b=char(strc201603{3}(i));
    b=strrep(b,'Inbound','1');
    b=strrep(b,'Outbound','0');
    b=strrep(b,'Clockwise','3');
    b=str2num(b);
    data03(i,11)=b;
    data03(i,12)= strc201603{6}(i);
    data03(i,13)= strc201603{8}(i);
    data03(i,14)= strc201603{9}(i);
data03(i,15)=strc201603{2}(i);
data03(i,16)=hour(strc201603{4}(i))*3600+minute(C_data0{4}(i))*60+second(C_data0{4}(i));
end;

I have used this code for 1 day data and it worked. But when I tried to run the code with 1 month data, the code is not working. It shows some error like:

**The following error occurred converting from cell to double:
Error using double
Conversion to double from cell is not possible.**

I couldn't understand why it shows this error. Please help.

Thanks, Faria

[Walter Roberson]

Which line is the error occurring on? What is class() and size() of all of the items mentioned on the right side of the assignment for that line? What is class() of the variable being assigned to?