Finding a row with a certain condition
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AA
am 22 Jun. 2016
Beantwortet: Star Strider
am 22 Jun. 2016
Assume I have the following matrix.
733458 91 1.01510000000000 1.01680000000000 1.01490000000000 1.01520000000000 1.01585000000000
733458 112 1.01620000000000 1.01620000000000 1.01400000000000 1.01610000000000 1.01510000000000
733458 135 1.01440000000000 1.01540000000000 1.01430000000000 1.01480000000000 1.01485000000000
733458 154 1.01420000000000 1.01580000000000 1.01410000000000 1.01420000000000 1.01495000000000
733458 173 1.01550000000000 1.01570000000000 1.01490000000000 1.01560000000000 1.01530000000000
I want to find the row that contains in column one the value 733458 and that is the closest to 158 in column 2. How can I do that?
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Azzi Abdelmalek
am 22 Jun. 2016
A=[733458 91 1.01510000000000 1.01680000000000 1.01490000000000 1.01520000000000 1.01585000000000
733458 112 1.01620000000000 1.01620000000000 1.01400000000000 1.01610000000000 1.01510000000000
733458 135 1.01440000000000 1.01540000000000 1.01430000000000 1.01480000000000 1.01485000000000
733458 154 1.01420000000000 1.01580000000000 1.01410000000000 1.01420000000000 1.01495000000000
733459 173 1.01550000000000 1.01570000000000 1.01490000000000 1.01560000000000 1.01530000000000]
ii=ismember(A(:,1),733458)
B=A(ii,:)
[~,jj]=min(abs(A(ii,2)-158))
out=B(jj,:)
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Star Strider
am 22 Jun. 2016
One approach:
x = 158;
idx = find((M(:,1) == 733458) & ((x-M(:,2)).^2) == min( (x-M(:,2)).^2));
idx =
4
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