How do I overcome the "Subscript Indices" problem?
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Firstly, I know what it is and why it happens. I just want to know how to overcome the problem.
My code is as followed:
b=zeros(3,3,3); %returns an n-by-n matrix of zeros.
a=[0 1 1; 1 0 1; 1 1 0];
[r, c]=size(a);
for i = 1:r
b(a(i,c-2),a(i,c-1),a(i,c)) = 1;
end
[m, n, o]=size(b);
figure (1)
[x,y,z] = meshgrid(1:m,1:n,1:o);
scatter3(x(:),y(:),z(:),90,b(:),'filled')
3 Kommentare
Walter Roberson
am 9 Jun. 2016
What is the aim of your statement
b(a(i,c-2),a(i,c-1),a(i,c)) = 1;
taking into account that some of those a values are 0?
Akzeptierte Antwort
John BG
am 9 Jun. 2016
Thomas
your are trying to index b with a null.
In MATLAB matrix indices have to be >0, and in your for loop you are trying to index b with elements of a, that some happen to be zero.
To index b you need 3 indices, that for instance could be
b(c-2,c-1,c) = 1;
This fixes the
'Subscript indices ..'
crash, yet since don't know the matrix you want to generate, cannot go anyfurther without knowing what do you really want in matrix b.
If you find this answer of any help solving your question,
please click on the thumbs-up vote link, or mark it as accepted
thanks in advance
John
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!