How do I overcome the "Subscript Indices" problem?

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Thomas
Thomas am 9 Jun. 2016
Kommentiert: Thomas am 9 Jun. 2016
Firstly, I know what it is and why it happens. I just want to know how to overcome the problem.
My code is as followed:
b=zeros(3,3,3); %returns an n-by-n matrix of zeros.
a=[0 1 1; 1 0 1; 1 1 0];
[r, c]=size(a);
for i = 1:r
b(a(i,c-2),a(i,c-1),a(i,c)) = 1;
end
[m, n, o]=size(b);
figure (1)
[x,y,z] = meshgrid(1:m,1:n,1:o);
scatter3(x(:),y(:),z(:),90,b(:),'filled')
  3 Kommentare
Walter Roberson
Walter Roberson am 9 Jun. 2016
What is the aim of your statement
b(a(i,c-2),a(i,c-1),a(i,c)) = 1;
taking into account that some of those a values are 0?
Thomas
Thomas am 9 Jun. 2016
I made this statement for a previous matrix that included no zeros

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John BG
John BG am 9 Jun. 2016
Thomas
your are trying to index b with a null.
In MATLAB matrix indices have to be >0, and in your for loop you are trying to index b with elements of a, that some happen to be zero.
To index b you need 3 indices, that for instance could be
b(c-2,c-1,c) = 1;
This fixes the
'Subscript indices ..'
crash, yet since don't know the matrix you want to generate, cannot go anyfurther without knowing what do you really want in matrix b.
If you find this answer of any help solving your question,
please click on the thumbs-up vote link, or mark it as accepted
thanks in advance
John
  1 Kommentar
Thomas
Thomas am 9 Jun. 2016
Thanks for the solution, it did fix the problem.
What I want to show are the three vectors [0 1 1] [1 0 1] [1 1 0] represented only by the spheres.
I did this successfully using vector arrows.
if true
% code
end
a = [0 1 1];
b = [1 0 1];
c = [1 1 0];
starts = zeros(3,3);
ends = [a;b;c];
quiver3(starts(:,1), starts(:,2), starts(:,3), ends(:,1), ends(:,2), ends(:,3))
axis equal
axis on
view(3), axis vis3d
camproj perspective, rotate3d on
end

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