Simple problem: Replacing a loop with a vector expression
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi all,
I'd like to run this by people here as I can't see where I'm going wrong, despite this seeming pretty simple.
I have the following loop:
for n=M+1:N
y(n)=a*x(n)+x(n-M)-a*y(n-M);
end
I wish to implement this as a vector expression. Here is what I have got:
y(M+1:N)=a*x(M+1:N)+x(1:N-M)-a*y(1:N-M);
I'd thought this was correct, but when I do simple (or complicated) examples, the values are only the same up to a certain point. I've noticed that they are correct up to the entry that is double of the value of M (so if M=8, the outputs produced by both examples are the same up until the 16th entry in the vector).
Can anyone have a look at this and correct me if I've made a mistake? As usual it may be something simple, but I'm not seeing it!
Craig
0 Kommentare
Antworten (1)
Jan
am 12 Feb. 2012
1 Kommentar
Jan
am 29 Jan. 2023
Bearbeitet: Jan
am 29 Jan. 2023
Austin Chen wrote a flag at 28 Jan 2023 at 3:22: "terrible response"
@Austin: You find an exhaustive discussion and some example code in this link.
If you know a better answer, feel free to post it.
Siehe auch
Kategorien
Mehr zu NaNs finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!