How I could convert matrix (double) to cell array of string

I have the following matrix and I want to convert it in cell array of string.

Please help me with this issue.

 A=[-1; -3; -5; -5; -6; -7; -9; -3; -7; -9; -8; -9; -10]

Answer 1

[Walter Roberson]

A_cell = cellstr(str2num(A));

[Maryam Hamrahi]

Many thanks for the answer. I used your code and I got the following error.

Error using str2num (line 32)

Requires string or character array input.

Error in (line 2) A_cell = cellstr(str2num(A))

[Walter Roberson]

A_cell = cellstr(num2str(A));

I don't know why I keep getting that reversed...

[Maryam Hamrahi]

Thank you very much.

[Irina Ciortan]

This is not correct. Str2num converts strings to numeric format, but the question was the other way around. The correct and best answer should be https://se.mathworks.com/matlabcentral/answers/286544-how-i-could-convert-matrix-double-to-cell-array-of-string#answer_331847

[Walter Roberson]

Look at the correction posted in May 2016

Answer 2

[Iskander]

Use undocumented function:

sprintfc('%d',A)

[Kyle Pastor]

This is the best implementation I have seen. Very nice!

[Patrick Bernier]

This needs to be higher ! Thanks !

[Andrew Winter]

Awesome! Thanks for this extremely concise method. As Patrick said, this needs to be higher!

[Neil Patel]

This functionality is basically the same as the documented function compose. Try

compose('%d',A)

[Walter Roberson]

Note: compose requires R2016b or later.

Answer 3

[Benny Abramovsky]

This one worked for me:

strsplit(num2str(A))

[Benny Abramovsky]

but it'll work only on row vector

[Syed Hussain]

This can work for a general matrix using

    strsplit(num2str(A(:)'))

and reshaping as necessary.

[Irina Ciortan]

This is correct answer and worked for me.

Answer 4

[Karolis Poskus]

Using one function:

compose('%g',A)

[Walter Roberson]

Already posted at https://www.mathworks.com/matlabcentral/answers/286544-how-i-could-convert-matrix-double-to-cell-array-of-string#comment_637933

[Kyuhwa Lee]

best answer

[Walter Roberson]

This, that you say is "best answer", is the same solution that was posted 23 months earlier at https://www.mathworks.com/matlabcentral/answers/286544-how-i-could-convert-matrix-double-to-cell-array-of-string#comment_637933

Also, at the time of the original question, compose() did not exist: the original question was May 2016, which was R2016a, but compose() was introduced as part of the string operations in R2016b.

Answer 5

[Rubén Vázquez Amos]

Wouldn't string(A) work?

[DGM]

I suppose it does, but to be fair, that wouldn't have been an option in early 2016.

[Rubén Vázquez Amos]

I did test it and it worked, but wasn't sure about 2016 compatibility so I figured I'd put it as a tentative answer.

[DGM]

As far as I know, string() was introduced in R2016b, but I don't know that it's early behavior was the same as it is today. I think it's safe to say the legacy options don't matter to most readers, and they'd probably be fine with your answer. The only reason I bring it up is to explain why it hadn't been mentioned at the time the question was asked.

Answer 6

[WinCento99]

Hi all,

If we define A as a matrix

A = [1 , 2 ; 3 , 4]

And we want to create a cell string matrix, do we do the following?

B = cellstr(num2str(A))
for i = 1:length(B)
    C(i,:) = strsplit(B{i,1}) ;
end

Is there a way to ignore the loop?

[Walter Roberson]

A = [1 , 2 ; 3 , 4]

A = 2×2

1 2 3 4

B = cellstr(string(A))

B = 2×2 cell array
    {'1'}    {'2'}
    {'3'}    {'4'}