How to do this in Matlab?

1 Ansicht (letzte 30 Tage)
Shivshankar R
Shivshankar R am 18 Mai 2016
Kommentiert: Andrei Bobrov am 18 Mai 2016
I have a following code
x=randi([1 150],1,400);
d=max(x);
m=numel(x);
y=zeros(d,1);
p=zeros(d,d);
for k=1:m-1
y(x(k))=y(x(k))+1;
p(x(k),x(k+1))=p(x(k),x(k+1))+1;
end
p=bsxfun(@rdivide,p,y);
p(isnan(p)) = 0;
j=prod(p(p~=0));
[~,~,idx] = unique(x);
q=prod(hist(idx,1:max(idx))/numel(x));
s=log(j);
l=log(q);
g=s+l
In above code random no. generated from 1 to 150 with sequence length 400. finally I am getting output g,suppose random no. sequence generated by code is
x=[5,96,96,55,55,65,65,65,12,12,6,7,9,9,9,31,31,14,26,26,26,101,101,145,145,...]
so code is given output for whole sequence, but i want output for sliding window of size 10, i.e. o/p for sequence
[5,96,96,55,55,65,65,65,12,12],
then skipping 1st element and adding next element so window size should remain same, i.e.
[96,96,55,55,65,65,65,12,12,6],
then next for
[96,55,55,65,65,65,12,12,6,7],
likewise up to last, how to do it.

Antworten (1)

Andrei Bobrov
Andrei Bobrov am 18 Mai 2016
Bearbeitet: Andrei Bobrov am 18 Mai 2016
x0 = [4,1,1,1,2,2,3,5,9,7,7,7,6,6,1,1,2,3,4,4];
n = 10;
m = numel(x0) - n + 1;
x1 = hankel(x0(1:end-n+1),x0(n+1:end));
g = zeros(m,1);
for jj = 1:m
x = x1(jj,:);
y = accumarray(x(:),1);
p = accumarray(hankel(x(1:end-1),x(end-1:end)),1);
p = bsxfun(@rdivide,p,y);
p(isnan(p)) = 0;
g(jj) = log(prod(y(y~=0)/numel(x))*prod(p(p~=0)));
end
  2 Kommentare
Shivshankar R
Shivshankar R am 18 Mai 2016
Matlab showing 'Undefined function or variable 'x''
Andrei Bobrov
Andrei Bobrov am 18 Mai 2016
corrected

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by