Problem with Modified Secant Method

Hi, could you help me this code. The answer which is the root of the equation will always be wrong when matlab shows the value of xrc which is the value for the final iteration. Feel free to contact me if there are any questions about my code. I have a feeling that my code has some error around the part where i request the user to input the desired equation. Thanks!

clc
i=1;
x(i)=x_0;
prompt3 = 'Enter the equation in terms of x(i):';
prompt = 'Enter value of step size: ';
prompt1 = 'Enter value of first x: ';
prompt2 = 'Enter the error percentage: ';

steps = input(prompt)
x_0 = input(prompt1)
error = input(prompt2)
z = input(prompt3)

eacurrent=100;
xrc=0
ea(i)=100;
while(eacurrent>0)
  
    F(i)= z

      x(i+1)= x(i) - ((F(i)*steps)/(F(i)+steps)-F(i));

      if (i>1)
          ea(i)=abs((x(i+1)-x(i))/x(i+1))*100;
          eacurrent=ea(i)
      end
      if (ea(i)>error)
          i=i+1
      else
          xrc=x(i+1)
          break
      end

end