Sort 3D matrix depending on specific column

Hello,

I have 3D matrix (10*10*4) and I am trying to short each slice depending on the 2 column after that and depending on column 2 I want to delete all rows that have a value on column 2 less than 1 and greater than 17.

I used this code to sort but it is not working

 clc;
clear;
A = rand(10,10,4)
column = 2;
[values,indices] = sort(A(:,column,:)) 
B = A(indices,:,:)

Thanks

[Azzi Abdelmalek]

After deleting some rows, your slices will get different sizes, have you thought about that?

[Ali Kareem]

Hello,

Thank you for your reply. No, it will the same. because this data is a grid and I checked that. but I will get new 3D matrix with new size

Answer 1

[Azzi Abdelmalek]

%-----------Example----------
A=randi(30,10,10,4)
%--------------------------------
out=cell(1,k);
for k=1:size(A,3)
  a=A(:,:,k);
  b=sortrows(a,2);
  c2=b(:,2);
  b(c2<1 | c2>27,:)=[];
  out{k}=b
end