Filter löschen
Filter löschen

How do I show that my matrix is unitary?

14 Ansichten (letzte 30 Tage)
Bryan Acer
Bryan Acer am 9 Mai 2016
Bearbeitet: Roger Stafford am 9 Mai 2016
I have a matrix H with complex values in it and and set U = e^(iH). My code to verify that U is a unitary matrix doesn't prove that U' == U^-1 which holds true for unitary matrices. What am I doing wrong? Thank you!
H = [2 5-i 2; 5+i 4 i; 2 -i 0]
U = exp(i * H)
UConjTrans = U'
UInverse = inv(U)
  3 Kommentare
Bryan Acer
Bryan Acer am 9 Mai 2016
Bearbeitet: Bryan Acer am 9 Mai 2016
The wording of the problem implies that H is hermitian and that U must therefore be a unitary matrix given by U = e^(i*H)
"show that H is hermitian." "Show U is unitary. (Recall a unitary matrix means U† = U−1)"
Roger Stafford
Roger Stafford am 9 Mai 2016
It is obviously true that H is Hermitian symmetric, but it does not follow that exp(i*H) is unitary, as you yourself have shown.
Note: The set of eigenvectors obtained by [V,D] = eig(H) can constitute a unitary matrix in such a case if properly normalized.

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Roger Stafford
Roger Stafford am 9 Mai 2016
Bearbeitet: Roger Stafford am 9 Mai 2016
The problem lies in your interpretation of the expression e^(i*H). It is NOT the same as exp(i*H). What is called for here is the matrix power, not element-wise power, of e. The two operations are distinctly different. Do this:
e = exp(1);
U = e^(i*H);
You will see that, subject to tiny rounding error differences, the inverse of U is equal to its conjugate transpose.
See:
http://www.mathworks.com/help/matlab/ref/mpower.html

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by