Why we use Transfer Function to represent/describe a Dynamic Model?

1 Ansicht (letzte 30 Tage)
Bob
Bob am 6 Mai 2016
Why we use Transfer Function to represent/describe a Dynamic Model?
%%Parameters
m1 = 2500; % Sprung Mass (kg)
m2 = 320; % Unsprung Mass (kg)
k1 = 80000; % Suspension Stiffness (N/m)
k2 = 500000; % Wheel and Tire Stiffness (N/m)
b1 = 350; % Suspension Damping Coefficient (N*s/m)
b2 = 15020; % Wheel and Tire Damping Coefficient (N*s/m)
%%Dynamic Model
% Displacement of Mass 1, G1(s) = X1(s)/W(s)
num1 = [(0) (0) (b1*b2) (b1*k2+b2*k1) (k1*k2)]; % Output X1(s)
den1 = [(m1*m2) (m1*b1+m1*b2+m2*b1) (m1*k1+m1*k2+m2*k1+b1*b2) (b1*k2+k1*b2) (k1*k2)]; % Input W(s)
G1 = tf(num1,den1);
% Displacement of Mass 2, G2(s) = X2(s)/W(s)
num2 = [(0) (m1*b2) (m1*k2+b1*b2) (b1*k2+b2*k1) (k1*k2)]; % Output X2(s)
den2 = [(m1*m2) (m1*b1+m1*b2+m2*b1) (m1*k1+m1*k2+m2*k1+b1*b2) (b1*k2+k1*b2) (k1*k2)]; % Input W(s)
G2 = tf(num2,den2);

Antworten (1)

Azzi Abdelmalek
Azzi Abdelmalek am 6 Mai 2016

Kategorien

Mehr zu Chassis Systems finden Sie in Help Center und File Exchange

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by