Hello!
Be
Z={'1.1 2.1 3.2 3.3 5.5 5.4'; '3 4 5 10 11 56'};
a 2*1 cell array.How can I split Z into a cell array with 2x6 cells? Notice that Z is composed by numbers.
Thanks a lot.

 Akzeptierte Antwort

Stephen23
Stephen23 am 25 Apr. 2016
Bearbeitet: Stephen23 am 25 Apr. 2016

2 Stimmen

Option One: Convert to Numeric
>> mat = [sscanf(Z{1},'%f'),sscanf(Z{2},'%f')].'
mat =
1.1000 2.1000 3.2000 3.3000 5.5000 5.4000
3.0000 4.0000 5.0000 10.0000 11.0000 56.0000
Best would be to leave it as a numeric array... however if you really need a cell array of numeric scalars, then use num2cell:
num2cell(mat)
Option Two: Keep as String
>> tmp = regexp(Z,'\S+','match');
>> tmp = vertcat(tmp{:})
tmp =
'1.1' '2.1' '3.2' '3.3' '5.5' '5.4'
'3' '4' '5' '10' '11' '56'

4 Kommentare

angelavtc
angelavtc am 25 Apr. 2016
Bearbeitet: angelavtc am 25 Apr. 2016
Dear stephen
Actually my cell array is of size 10*1 cell and it goes like this:
[199001031001.000;199001031006.000;199001031011.000] [199001031002.000;199001031007.000;199001031012.000] [199001031003.000;199001031008.000;199001031013.000] [199001031004.000;199001031009.000;199001031014.000] [199001031005.000;199001031010.000;199001031015.000]
[199001031006.000;199001031011.000]
[199001031007.000;199001031012.000]
[199001031008.000;199001031013.000]
[199001031009.000;199001031014.000]
[199001031010.000;199001031015.000]
is there a way to decompose it and have each of its elements in one cell?
angelavtc
angelavtc am 25 Apr. 2016
Becase when I use your code it says "Error using regexp All cells must be strings" which makes sense because they are not actually strings but numbers. Can you help me to solve this problem?
Thanks a lot
Stephen23
Stephen23 am 26 Apr. 2016
Bearbeitet: Stephen23 am 26 Apr. 2016
@angelavtc: That example with numeric vectors inside a cell array cannot be trivially converted to a single array with each numeric element in its own cell, because you have different number of elements in each vector. You could try experimenting with these FEX submissions:
Note that you can supply the contents of a cell array by using a comma separated list:
inp = {[...],[...]}
out = padcat(inp{:})
angelavtc
angelavtc am 30 Apr. 2016
Thanks a lot!!!

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