“if” statement using “or” operator.

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Sarah
Sarah am 2 Feb. 2012
Kommentiert: Lewis Waswa am 9 Jan. 2023
Hello everyone,
I have a very simple question....and I have been working on it for some time but cannot figure it out. This is essentially what I would LIKE to say:
for r = 1:length(FreqSec)-1
if FreqSec(1,r+1) > FreqSec(r)*1.01 "OR" FreqSec(1,r+1) <FreqSec(r)*0.99
LagStart = [FreqSec(1,r) r];
break;
end
end
FreqSec is a vector with lots and lots of values....generally within the range of 0.99 and 1.01, except for in a certain interval. I want to detect the exact index point at which the values start changing from the 0.99 to 1.01 range.
Thanks for the help in advance :)
  1 Kommentar
Aaron Eldridge
Aaron Eldridge am 28 Apr. 2016
The "||" counts as an or on matlab

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Akzeptierte Antwort

Walter Roberson
Walter Roberson am 3 Feb. 2012
if FreqSec(1,r+1) > FreqSec(r)*1.01 | FreqSec(1,r+1) <FreqSec(r)*0.99
or
if FreqSec(1,r+1) > FreqSec(r)*1.01 || FreqSec(1,r+1) <FreqSec(r)*0.99
The first of these is more general. The second of these, , is the short-circuiting OR that does not bother to evaluate the second expression if it already knows the final result after the first operation. The operator can only be used between expressions that produce scalar outputs.
  3 Kommentare
Maximiliano Barbosa
Maximiliano Barbosa am 1 Dez. 2022
Thank you
Lewis Waswa
Lewis Waswa am 9 Jan. 2023
A quick question, does this mean that the | evaluattes all the conditions?

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Weitere Antworten (2)

Geoff
Geoff am 3 Feb. 2012
So you want the last index within the valid range?
I don't know why you are multiplying by 1.01 and 0.99. Perhaps you have described the problem incorrectly or that is the cause of your difficulties. What I think you are trying to do is this:
idx = find( FreqSec >= 0.99 & FreqSec <= 1.01, 1, 'last' )
LagStart = [FreqSec(1,idx) idx];
Or, since it's symmetric:
idx = find( abs(FreqSec-1) <= 0.01, 1, 'last' )
If instead you want the index of the first out-of-range value, use:
idx = find( abs(FreqSec-1) > 0.01, 1, 'first' )
The parameter 'first' is optional, but good for clarity.
-g-
  1 Kommentar
Geoff
Geoff am 3 Feb. 2012
Oops, those statements with 'last' are incorrect. You are probably better off doing the 'first' statement and subtracting 1.

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Rehman Tabasum
Rehman Tabasum am 30 Apr. 2021
i=5
while i>=-1
pause(1)
fprintf('%d\n',i)
i=i-1
if i==0
break
end
end
this is my code for the start button gui for countdown timer so anyone know how to stop coutdown timer when it is runnnig

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