Impedance calculation from experimental data

36 Ansichten (letzte 30 Tage)
Gisela
Gisela am 11 Apr. 2016
I have some experimental data (V and I) that I want to use to calculate the impedance Z using matlab. So far I've calculated the Fourier transform for both voltage and current and to calculate the impedance I want to determine the ratio between the two of them. This however gives a vector for each frequency and in order to obtain the Nyquist plot I need to use only one of the values of the vector. Yet I don't know which of the values I have to choose.

Akzeptierte Antwort

Star Strider
Star Strider am 11 Apr. 2016
I do not understand what your data are. Do you have a vector or matrix?
Ideally, you would either have the voltage and current measured at each frequency, or the impulse response of which you took the fft. Impedance Z(jω) is by definition a complex quantity, so you would simply calculate Z=V./I to get the complex impedance.
  3 Kommentare
Star Strider
Star Strider am 11 Apr. 2016
Without knowing more about your experimental set-up, I would just take the means of the complex voltage and current data at each frequency. That would work to begin with. If it produces acceptable results, go with it. If not, experiment (for example a different plot for each run, then compare them). To do the mean, the frequencies have to be exactly the same (or as close as your instrumentation allows).
Ruben Díaz Granero
Ruben Díaz Granero am 13 Mai 2021
Hi! Have you solved your problem? I've exactly the same problem. An Input current data with a voltage response from a modeling circuit. I(t) --> H(s) --> V(t). The teorical solution is applying the FFT to each temporal sine wave and you will obtain I(w) and V(w). Then the ratio V(w)/I(w) it is supposed to be the impedance Z(jw) but I can't reach this point.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Electrical Block Libraries finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by