I would like to make an equation to solve t when T_max is equal to 450

OC=[3/5;3/5*sqrt(3);0]
BC=[9/40*sqrt(3);27/40;9/20]
OB=OC+BC
R=OB
syms t
F=[0;0;t]
MO=cross(R,F)
OA=[0;1.2;0.9]
OAe=OA/norm(OA)
Max=dot(OAe,MO)*OAe
T_max=norm(Max)

Answer 1

[Roger Stafford]

It is simple division:

   t = 450/dot(OAe,cross(R,[0;0;1]));   (<-- Corrected)

Answer 2

[sam0037]

Hi,

Appending these three commands to your code will do the magic:

eqn = T_max == 450;
res = solve(eqn,t);
val = double(res); %this is the desired value of t

Here are the documentation links for the same:

http://www.mathworks.com/help/releases/R2015b/symbolic/solve.html#bue1f92-1

http://www.mathworks.com/help/symbolic/double.html