function to solve a binary matrix?

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Firas Al-Kharabsheh
Firas Al-Kharabsheh am 1 Apr. 2016
If i have a binary matrix (NxM)
A =[0 0 1 0 1 0 1 0 1 0 1 0 1 0 0 1
0 1 1 0 1 1 1 1 1 1 1 1 0 1 0 1
1 1 0 1 0 0 0 0 0 0 0 1 1 1 1 1
0 1 0 1 1 1 0 0 0 0 0 1 1 1 1 1
0 1 1 1 1 0 1 0 0 1 1 1 1 1 0 1
0 0 1 1 0 1 1 0 1 1 1 0 1 0 0 1
0 1 0 0 1 0 1 1 1 1 0 1 1 1 0 1
0 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
0 0 0 0 0 1 1 1 1 1 0 0 0 0 0 1];
I need a function to calculate number of 1 and in each row and put it in a new matrix like this
B = [ 1 1 1 1 1 1 1
2 8 1 1
2 1 5
1 3 5
4 1 5 1
2 2 3 1 1
1 1 4 3 1
13
15
5 1 ]
And a third matrix for a column like this
C = [ 1 4 2 4 2 1 2 1 2 1 2 4 1 4 2 7
1 3 2 2 2 1 6 4 5 6 2 3 7 3 1 2
2 3 1 2
3 ]
  • Note when the counter see zero then the counter will be stop and start again for example [0 1 1 0 1 1 1 1 1 ] then the solution will be [2 5]

Akzeptierte Antwort

Azzi Abdelmalek
Azzi Abdelmalek am 1 Apr. 2016
A =[0 0 1 0 1 0 1 0 1 0 1 0 1 0 0 1
0 1 1 0 1 1 1 1 1 1 1 1 0 1 0 1
1 1 0 1 0 0 0 0 0 0 0 1 1 1 1 1
0 1 0 1 1 1 0 0 0 0 0 1 1 1 1 1
0 1 1 1 1 0 1 0 0 1 1 1 1 1 0 1
0 0 1 1 0 1 1 0 1 1 1 0 1 0 0 1
0 1 0 0 1 0 1 1 1 1 0 1 1 1 0 1
0 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
0 0 0 0 0 1 1 1 1 1 0 0 0 0 0 1]
[n,m]=size(A);
B=(m+repmat(1:m,n,1)-A.*cumsum(A,2)).*A;
for k=1:n
a=B(k,B(k,:)~=0);
[~,~,kk]=unique(a);
row1{k,1}=accumarray(kk,1);
end
celldisp(row1)
  4 Kommentare
Firas Al-Kharabsheh
Firas Al-Kharabsheh am 1 Apr. 2016
Thank you

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