Roots of a function
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I have two equations:
y1 = 2sinx1;
y2 = 2cos^2(x1) + 3sin(2x2+3);
here y1 = 0 while y2 = 1.
Can anyone please tell me which approach would be the best to find out the values of x1 and x2.
Thank you.
1 Kommentar
Torsten
am 30 Mär. 2016
x1=0
x2=(asin(-1/3)-3)/2
Best wishes
Torsten.
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Vlad Miloserdov
am 30 Mär. 2016
if you still need this
A=solve('0 = 2*sin(x1)','1 = 2*cos(x1)^2 + 3*sin(2*x2+3)','x1','x2');
% first ans
A.x1(1)
A.x2(1)
% second ans
A.x1(2)
A.x2(2)
5 Kommentare
Muhammad Umar Farooq
am 31 Mär. 2016
Torsten
am 31 Mär. 2016
You have two equations - thus you will need MATLAB's "fsolve".
Best wishes
Torsten.
Muhammad Umar Farooq
am 31 Mär. 2016
Torsten
am 31 Mär. 2016
Please show your code.
Best wishes
Torsten.
Muhammad Umar Farooq
am 31 Mär. 2016
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