suppressing output from user defined function

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Michael
Michael am 25 Mär. 2016
Kommentiert: Voss am 25 Feb. 2024
function f=fib(n);
f=ones(n,1);
for i=1:n-2;
f(i+2,1)=f(i+1,1)+f(i,1);
end;
i have this function to calculate fibbonaci sequence, but i get outputs despite having semicolons on everything.
Can anyone tell me why?

Akzeptierte Antwort

Jonathan Chin
Jonathan Chin am 25 Mär. 2016
When you call your function use a semi colon at the end of the function to suppress the output.
try f=fib(n) and f=fib(n); in the command line to see the results
  1 Kommentar
Michael
Michael am 25 Mär. 2016
Bearbeitet: Michael am 25 Mär. 2016
worked. i'm an idiot -_- Thanks man.

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Weitere Antworten (1)

Walter Roberson
Walter Roberson am 25 Mär. 2016
You have to put a semi-colon in the line that calls fib() to prevent the default output
abc = fib(19)
fib is called and returns an expression that is assigned to the variable, but the default action for assignment is to also display the result of the assignment. You would need
abc = fib(19);
to suppress it.
This is not under the control of the called function, which does not have control by the time MATLAB makes the decision about whether to output or not.
  5 Kommentare
Yevgeniy Gorbachev
Yevgeniy Gorbachev am 25 Feb. 2024
@Voss Exactly the behavior I'm looking for, thank you!
Voss
Voss am 25 Feb. 2024
You're welcome!

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