array length is not what I've set...
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
beginner
am 23 Mär. 2016
Bearbeitet: Jos (10584)
am 23 Mär. 2016
Hi,
This is my code, it works just fine, just I dont understand why my array Hopt_new is generating more arrays than I set.
Bo=1;
X = 0:0.1:3;
Hopt_new = zeros([1 90]);
h0_new = 0;
for j = 90:1:179
theta = j*pi/180;
handle = @(h0) test2fun(h0, theta, Bo,X);
Hopt_new(j)=fsolve(handle, h0_new);
h0_new = Hopt_new(j);
end
Why does Hopt_new have length of 179 instead of 90, which I set before the for loop? Is this because j goes until 179? I mean j actually is a "vector" with length of 90. I just dont get it.
Thanks a lot.
1 Kommentar
Jos (10584)
am 23 Mär. 2016
Yes, take a look at this code, and then see my answer:
A = [1 2 3]
A(6) = 99
Akzeptierte Antwort
random09983492
am 23 Mär. 2016
The first time the loop executes it sets Hopt_new(90).
The second time it sets Hopt_new(91).
If you want to start at the first index of Hopt_new, assign Hopt_new(j-89) rather than just Hopt_new(j).
0 Kommentare
Weitere Antworten (1)
Jos (10584)
am 23 Mär. 2016
Bearbeitet: Jos (10584)
am 23 Mär. 2016
In your code, the variable j has two roles:
- an index into Hopt
- a value that is used for calculation (angle?)
Your best option is to disentangle these using two variables:
Bo = 1;
X = 0:0.1:3;
Hopt_new = zeros([1 90]);
h0_new = 0;
Angle = 90:1:179 ;
for j2 = 1:numel(Angle)
% loop over all angles
theta = Angle(j2) * pi/180;
handle = @(h0) test2fun(h0, theta, Bo, X);
Hopt_new(j2) = fsolve(handle, h0_new);
h0_new = Hopt_new(j2);
end
0 Kommentare
Siehe auch
Kategorien
Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!