Ouputting for loop into a matrix
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Hi guys
I have a function called 'simulator' that has two inputs, Cl and Cd. The function outputs a Time around a circuit for these inputs.
I want to be able to execute a loop that runs a combination of Cls and Cds between 0 and 3, and to output all the resulting times into a matrix, and THEN to be able to find the smallest time and Matlab to tell me what time this is, and what Cl and Cd combination this was.
Has anyone any idea how to go about this code? So far I have...
for i=[0.1:0.1:3]; j=[0.1:0.1:3]; a=[1:1:30]; y(a)= simulator([(i) (j)]) end
But I'll be honest, it doesn't really work at all...
Many thanks in advance guys!
Tom
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Antworten (2)
Vieniava
am 8 Mär. 2011
Try this:
Ci=0.1:0.1:30;
Cd=0.1:0.1:30;
y=zeros(numel(Ci), numel(Cd));
for i=1:numel(Ci)
for j=1:numel(Cd)
y(i,j)=simulator([ Ci(i) Cd(j) ]);
end
end
imagesc(y)
[v i]=min(y);
[II JJ]=ind2sub(size(y), i);
sprintf('The smallest time %f is for Ci=%f and Cd=%f', v,Ci(II),Cd(JJ))
3 Kommentare
Jan
am 8 Mär. 2011
Simpler finding of minimal value using linear indexing:
[v, ind] = min(y(:));
sprintf('The smallest time %f is for Ci=%f and Cd=%f', v, Ci(ind), Cd(ind));
Paulo Silva
am 8 Mär. 2011
y=zeros(1,30);
i=[0.1:0.1:3];
j=[0.1:0.1:3];
for pos=1:numel(i)
y(pos)=simulator([i(pos) j(pos)])
end
fprintf('The minimum time was %d for i=%d and j=%d',min(y),i(y==min(y)),j(y==min(y))
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