Exponential random number generation

hi,
How to generate the exponential random numbers from uniform random number generator?
thx

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the cyclist
the cyclist am 27 Jan. 2012

1 Stimme

lambda = 2;
x = -log(rand(1,1000000)/lambda)

4 Kommentare

King Fisher
King Fisher am 27 Jan. 2012
thx cyclist !
King Fisher
King Fisher am 27 Jan. 2012
But is there no general way, to generate any desired distributed random numbers by knowing its psd and uniform random number generator?
James Tursa
James Tursa am 27 Jan. 2012
Theoretically, one can invert the Cumulative Distribution Function and then plug uniform random numbers into that. Inverting the CDF is not always easy to accomplish, however.
the cyclist
the cyclist am 27 Jan. 2012
+1 to what James just wrote. If you search "generate random variate", you will find plenty to read. The book (remember those?) "Numerical Recipes" has a digestible discussion of the topic.

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