Hi, so I'm trying to plot this equation: y=-(sqrt(288-2*x.^4))/x with x=0:0.05:3.267 but y is giving me a single answer (-6.55) and when i do plot(x,y) the graph is empty! Can someone help me please!

Hi, so I'm trying to plot this equation: y=-(sqrt(288-2*x.^4))/x with x=0:0.05:3.267 but y is giving me a single answer (-6.55) and when i do plot(x,y) the graph is empty! Can someone help me please!

Answer 1

[Ingrid]

you have forgotten to also use the ./ operator instead of the / operator. The code below should give what you try to achieve

x=0:0.05:3.267;
y=-(sqrt(288-2*x.^4))./x;
plot(x,y)

Answer 2

[Torsten]

You forgot a dot (.) in front of "/x".

Best wishes

Torsten.

Answer 3

[Jos (10584)]

The plot is not empty. It contains 66 points all having the same y value (at y=-6.5514), which can be seen here:

plot(x,y,'bo')

Why is y a scalar? Because, as others told you already, there is a difference between element-wise (.* and ./) and matrix operators (* and /):

x = 1:4
x ./ x
x / x