Integration with variables as constants
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi,
I'm trying to integrate the following function with respect to r from 0 to inf:
4 3
4 r z
---------------
3 / 2 r z \
a exp| ----- |
\ a /
My question: How can I get a numerical value (double) while leaving Z and a as just constants in variable form?
For example, something in the form of 0.566 Z/a where Z and a are kept as just variables but the rest is evaluated to a number?
Thanks
2 Kommentare
Antworten (1)
Andrew Newell
am 25 Jan. 2012
If your symbolic expression is y, you can use
yInt = int(y,r,0,Inf);
EDIT: However, you may not get a clear answer. I don't have the Symbolic Toolbox, but in Maple I have to specify that a>0 and z>0 before it gives me an algebraic expression.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Numerical Integration and Differentiation finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!