Copyfile with variable in the pathname

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Marc-André Lemieux
Marc-André Lemieux am 24 Jan. 2012
Kommentiert: Walter Roberson am 7 Apr. 2020
Hi,
I want to copy some file but the path were they are going has a variable in its name
ex:
for compteur=1:1 nomaccel=fscanf(fidacc2,'%s',1); % read the name of the folder in a file
copyfile('LireDonneesDH.m','..\nomaccel\','f') %nomaccel is the variable copyfile('CompterLigne.m','..\nomaccel\','f') copyfile('GraphiqueDH.m','..\nomaccel\','f') cd (nomaccel); run GraphiqueDH cd .. end
So Matlab needs to understand that nomaccel is a variable.
I'm not sure how to do this
Thx for helping me !

Antworten (2)

Walter Roberson
Walter Roberson am 24 Jan. 2012

Polop Pilipi
Polop Pilipi am 7 Apr. 2020
Bearbeitet: Polop Pilipi am 7 Apr. 2020
Hello french fellow, you may be old now but for people coming on this page i would like to try an answer :
I would define first the path with dynamic strings :
destination_file_name = fscanf(fidacc2,'%s',1); % read the name of the folder in a file
destination_file_path = ([ '..\' , destination_file_name , '\' ]) %which gives > destination_file_path = '..\destination_file_name\'
%if you want to use numbers in the file name, you can also use 'num2str' function in the destination_file_path variable
copyfile('LireDonneesDH.m',destination_file_path,'f')
  1 Kommentar
Walter Roberson
Walter Roberson am 7 Apr. 2020
We recommend using fullfile() instead of concating together directories as character vectors.

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