Filter löschen
Filter löschen

How to take seasonal average of monthly values?

2 Ansichten (letzte 30 Tage)
SONI SONI
SONI SONI am 11 Feb. 2016
Bearbeitet: dpb am 11 Feb. 2016
Hello, I have 10 years (120 months) temperature data set. Now I want to take seasonal average of these monthly dataset. season 1 (Jan, Feb, Mar), season 2 (apr, may, june), season 3 (july, aug, sep) and season 4(oct, nov, dec) for every year. Final time series will represent 30 values. Can anyone help me to solve this problem?
  2 Kommentare
Andrei Bobrov
Andrei Bobrov am 11 Feb. 2016
Please, small example your temperature data.
SONI SONI
SONI SONI am 11 Feb. 2016
Temperature in celsius for a year
Jan 13.34, Feb 16.23, Mar 20.07, Apr 27.02, May 29.07, June 27.36, July 26.17, Aug 25.84, sep 25.55, oct 23.04, Nov 18.74, dec 14.71
Simillarly I have 10 year monthly temperature data.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

dpb
dpb am 11 Feb. 2016
Bearbeitet: dpb am 11 Feb. 2016
Depends on storage order...if 10x12 (years x months), then
Tseas=mean(reshape(T.',3,[]));
If it's already in column order by year, ditch the transpose .'

Weitere Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by