How do I plot data from a structure with time?

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Kieran Reeves
Kieran Reeves am 4 Feb. 2016
I have a structure with time from my scope in Simulink sent back to Matlab. I am unsure of what script code to use in Matlab to plot the data against time as I see it in the scopes in Simulink.
The structure is called Control_Logic
The signals area as follows.
How do I plot each individual signal vs time? Thanks Kieran
  2 Kommentare
Walter Roberson
Walter Roberson am 4 Feb. 2016
Could you show us
fieldnames(Control_Logic.signals)
and also if you could drag the divider between "values" and "dimensions" further right on the information, then you should be able to see the full information about the size of the first field; we can see it is 108350 by something but we cannot see what at the moment.
Kieran Reeves
Kieran Reeves am 4 Feb. 2016
Hi Walter
>> fieldnames(Control_Logic.signals)
ans =
'values'
'dimensions'
'label'
'title'
'plotStyle'
Which appear to just be the column titles
Kieran

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Akzeptierte Antwort

Guillaume
Guillaume am 4 Feb. 2016
Bearbeitet: Guillaume am 4 Feb. 2016
Most likely, this will work:
plot(Control_Logic.time, [Control_Logic.signals.values])
The [Control_Logic.signals.values] concatenates the values field of the 3 signal structures together into a 108350 x 3 matrix (assuming that values is 108350 x 1).
  3 Kommentare
Guillaume
Guillaume am 4 Feb. 2016
subplot(2, 2, 1); plot(Control_Logic.time, Control_Logic.signals(1).values);
subplot(2, 2, 2); plot(Control_Logic.time, Control_Logic.signals(2).values);
subplot(2, 2, 3); plot(Control_Logic.time, Control_Logic.signals(3).values);
is one way to do it.
Kieran Reeves
Kieran Reeves am 4 Feb. 2016
Thank you so much.

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Lars Lindner
Lars Lindner am 9 Nov. 2018
Hi everybody, I have the exact same problem. Trying the command
plot(data.time, data.signals(1).values)
gives me the error shown in following image:
Does anybody has an idea, what I am doing wrong?
Thanks everybody and with nice greetings, Lars
  1 Kommentar
LUIS ANGEL OLVERA OLVERA
LUIS ANGEL OLVERA OLVERA am 20 Nov. 2018
Hi,
You have an issue using singleton dimensions, please review "squeeze"
squeeze Remove singleton dimensions.
B = squeeze(A) returns an array B with the same elements as
A but with all the singleton dimensions removed. A singleton
is a dimension such that size(A,dim)==1. 2-D arrays are
unaffected by squeeze so that row vectors remain rows.
NewArray=squeeze(data.signals(1).values)
This function will turn your initially (1,1,10161) structure to a new (10161,1) array which can be used with your time array
To graph:
plot(data.time, A)
I hope this is useful for your project!
Luis Olvera

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