IFFT of a Hanning windowed FFT Image

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Luke Dineen-Woolnough
Luke Dineen-Woolnough am 27 Jan. 2016
Kommentiert: rashmi deshpande am 26 Aug. 2021
Hi, Im Trying to IFFT a Hanning Windowed FFT Image for the code below, to obtain the original image.
w = hanning(434)*hanning(362)'; fft = fftshift(fft2(Pixel_Reassign)); fft = abs(fft); [24 100000]; colormap gray; fftimage = log(fft+1).*w; figure, imshow(fftimage,[]);
Can anyone suggest how i go about this, i've tried to simply IFFT the fft output but i dont seem to get the original image back.
Thanks
Luke
  2 Kommentare
Luke Dineen-Woolnough
Luke Dineen-Woolnough am 28 Jan. 2016
The beggining of my ifft line looks like this
ifft = fftshift(ifft2(ifftshift(fft1))); ifft1 = log(abs(ifft));[24 100000]; colormap gray;
but there seems to be something inherently wrong with it.
any help would really be appreciated.
rashmi deshpande
rashmi deshpande am 26 Aug. 2021
Thanks a lot

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Mona Mahboob Kanafi
Mona Mahboob Kanafi am 28 Jan. 2016
Bearbeitet: Mona Mahboob Kanafi am 28 Jan. 2016
Hello,
You have used your absolute values to plot your image. Now, to reverse the operation you need the full fft results which is a complex matrix for regenerating your input image. Otherwise, you get something else!
Each fft component has value and phase. You shouldn't ignore the phase component which is ignored when you only use absolute values.
This is what you should do:
w = hanning(434)*hanning(362)';
FFT = fftshift(fft2(w)); % complex matrix
FFT_abs = abs(FFT); % absolut values of fft
imagesc(1+log10(FFT_abs)) % show fft results
w_new = ifft2(ifftshift(FFT)); % you need fft not fft_abs
Hope it helps,
Mona
  1 Kommentar
Luke Dineen-Woolnough
Luke Dineen-Woolnough am 28 Jan. 2016
Thank You So much Mona, that helps a lot.
Take Care
Luke

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