function [A]=AccGold()
n = 4;
while Gold(n)-Gold(n-1) > 0.00000001
n = n+1;
A = Gold(n)
end
end
I want to find the first value of Gold(n)-Gold(n-1) such that it is < 0.0000001

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Walter Roberson
Walter Roberson am 25 Jan. 2016
Bearbeitet: Walter Roberson am 25 Jan. 2016

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If the condition is immediately false you never assign to A.

2 Kommentare

Joshua Hall
Joshua Hall am 25 Jan. 2016
I want the loop to run until n is such that Gold(n)-Gold(n-1)<0.0000001, and then I want the value of Gold(n) at this n. Is there an easy way to change my function to do this?
Walter Roberson
Walter Roberson am 25 Jan. 2016
Initialize A=Gold(n)

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