I am trying to plot, at x=pi/4, the variation of the error percentage along h (h increments from 0.01 to 0.5), using the first order central difference method for function f(x)=sinx. Can't figure out what's wrong with the code. Any help please?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
z = cos(pi/4);%Exact value
n=0;
for h=0.01:0.01:0.5;
n=n+1;
t(n) =((sin(pi/4)+(h))-(sin(pi/4)-(h)))/(2*h);
Percent_Error(n)= abs (((t(n)-(z))./z)*100);
end
hold on
plot (t, Percent_Error);
0 Kommentare
Antworten (1)
Roger Stafford
am 5 Jan. 2016
Bearbeitet: Roger Stafford
am 5 Jan. 2016
What you want for t(n) is:
t(n) =(sin(pi/4+h)-sin(pi/4-h))/(2*h);
In other words the increment 'h' should be applied to the argument of the sine function, not outside it.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Line Plots finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!