I am trying to plot, at x=pi/4, the variation of the error percentage along h (h increments from 0.01 to 0.5), using the first order central difference method for function f(x)=sinx. Can't figure out what's wrong with the code. Any help please?

z = cos(pi/4);%Exact value
n=0;
for h=0.01:0.01:0.5;
n=n+1;
t(n) =((sin(pi/4)+(h))-(sin(pi/4)-(h)))/(2*h);
Percent_Error(n)= abs (((t(n)-(z))./z)*100);
end
hold on
plot (t, Percent_Error);

Antworten (1)

What you want for t(n) is:
t(n) =(sin(pi/4+h)-sin(pi/4-h))/(2*h);
In other words the increment 'h' should be applied to the argument of the sine function, not outside it.

Kategorien

Mehr zu Creating, Deleting, and Querying Graphics Objects finden Sie in Hilfe-Center und File Exchange

Gefragt:

MF
am 5 Jan. 2016

Bearbeitet:

am 5 Jan. 2016

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by