Reducing matrix dimension to a lower dimension

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MiauMiau
MiauMiau am 22 Dez. 2015
Kommentiert: MiauMiau am 22 Dez. 2015
Hi all,
I have a 1 x 400 x 16 matrix (400 measurements, 16 times). I would like to end up simply with a 400 x 16 matrix. Though when I use
reshape(X, [400,16])
it seems that the 400 rows do not correspond to the 400 measurements of one iteration, but that the data is all mixed up. How can I get the dimension I want?
Thanks
  2 Kommentare
Renato Agurto
Renato Agurto am 22 Dez. 2015
Your commad semms to be right. Maybe is the way you are looking at the 1x400x16 matrix.
display(X)
Matlab will show 16 arrays horizontally, which may make you think that the matrix is transposed.
what is the result of size(X)? it is really [1 400 16] ?
MiauMiau
MiauMiau am 22 Dez. 2015
Hi
Yes, indeed:
>> size(X)
ans =
1 400 16
So for reshape(X,[16,400]) the first row of the columns 1 to 9 is:
-21.0249 -22.2957 -18.9817 -18.0000 -14.7391 -15.5531 -17.2633 -16.4054 -14.0155
(so basically the 9 first measurements of the first measurement (of 16))
But, looking at X, the first 9 column of val(:,:,1) (which is the data from the first measurement from the 16 measurements, so it is up to val(:,:,16) ) are:
-21.0249 -22.5019 -24.1185 -25.7687 -27.3287 -28.6710 -29.6799 -30.2676 -30.3871
..not quite the same.

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Ingrid
Ingrid am 22 Dez. 2015
it looks like it is the squeeze command that you are looking for? Have you tried this:
squeeze(X);

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