How to replace image portion with processed image?

I have one rgb image. I crop one portion by using imcrop function. After lots of processing I want to place that processed portion into the same place of the orginal image. How can I do that. I tried by using imfusion but its not worked.

Answer 1

[Image Analyst]

Since you cropped it, you know what the starting and stopping rows and columns are. So just assign:

originalImage(row1:row2, col1:col2, :) = processedImage;

[rupam baruah]

Thank u. I crop the image using imrect. But how can I find the starting and stopping rows and columns are.

h = imrect;

position = getPosition(h);

handles.croppedImage = imcrop(handles.orginalImage, position);

[Image Analyst]

position is [leftColumn, topRow, width, height] I believe - isn't it? So to get the other side you just simply add the width or height to the first side.

col1 = position(1);
col2 = col1 + position(3);
row1 = position(2);
row2 = row1 + position(4);

[rupam baruah]

Yes. I got it. Thank you Sir.

[Subhadeep Koley]

Thank you Image Analyst

Answer 2

[Gosselin Thibault]

Hello everybody ! Sorry to view this long date post only but i've the same problem and your solution don't work on my program.

I have this error message : "Unable to perform assignment because the size of the left side is 118-by-325 and the size of the right side is 912-by-1200."

for this line code : Icrop1(row1:row2, col1:col2) = I;

Thank you for your help !!

[Image Analyst]

Without your program, all I can say is to make sure your (badly-named) I is 118-by-325. Use imresize() if you think that's appropriate.

[Gosselin Thibault]

I fixed my problem; i have just interchanged the originalImage and the processedImage. So yes it was very badly named !

But this solution did not resolve my problem because I also draw a curve on the modified image. I do not know how to draw the equivalent curve on the initial image.

Thank you for your repply and you help !

[Duyen Ho]

how did you fix the problem? im getting the same error

[Image Analyst]

He said he had

processedImage(row1:row2, col1:col2, :) = originalImage;

when he should have had

originalImage(row1:row2, col1:col2, :) = processedImage;

like I said. When he "interchanged the originalImage and the processedImage" he got my code and it worked. In short, the bigger matrix is on the left, and the smaller submatrix is on the right.