How to keep count in a nested for loop?

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john
john am 17 Nov. 2015
Bearbeitet: baby am 26 Sep. 2021
Hi, I'm sure the answer is simple but I just can't figure it out. Let's say I have this code:
for i=1:3
for j=1:3
count=??;
end
end
count
I want the result to be count=[1 2 3 4 5 6 7 8 9]
Thanks

Antworten (2)

the cyclist
the cyclist am 17 Nov. 2015
There are many ways to do this. Here is one.
c = 0;
for i=1:3
for j=1:3
c=c+1;
end
end
count = 1:c
  1 Kommentar
baby
baby am 26 Sep. 2021
Bearbeitet: baby am 26 Sep. 2021
you saved my life.

Melden Sie sich an, um zu kommentieren.


the cyclist
the cyclist am 17 Nov. 2015
Here is one way:
irange = 1:3;
jrange = 1:3;
for i=irange
for j=jrange
end
end
count = 1:(numel(irange)*numel(jrange));

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