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Change matrix elements in a loop?

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lsutiger1
lsutiger1 am 6 Nov. 2015
Kommentiert: Star Strider am 6 Nov. 2015
I am trying to figure out how to use a for loop to change the elements in a matrix.
I want to do this ten times.
For example, if row 1 of a 6x3 matrix is (a,a,0), I want to make a loop that generates row 2 as (2a,2a,0). I am basically trying to multiply the initial row to make all 6 rows increase by a multiple of a.
Thank you in advance for any suggestions!

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Star Strider
Star Strider am 6 Nov. 2015
No loop necessary. Use bsxfun:
M = randi(9, 6, 3);
Mm = bsxfun(@times, M, [1:size(M,1)]')
This multiplies every row of ‘M’ by the column vector [1 2 ... 6]'.
  8 Kommentare
lsutiger1
lsutiger1 am 6 Nov. 2015
Yes, I changed it because I was getting that error; neither the 1 or 3 seems to make a difference. This is why I am confused.
Star Strider
Star Strider am 6 Nov. 2015
I can’t run your code because I have no idea what you are doing and the inputs should be. Please attach a .mat file with the appropriate size and values for ‘type’. Use the ‘paperclip’ icon, and complete both the ‘Choose file’ and ‘Attach file’ steps.
My code does what you want it to, as you requested, but I can’t troubleshoot it with your code without the appropriate data.

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