Error using the integral function - A and B must be floating-point scalars.
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
cmilk
am 4 Nov. 2015
Kommentiert: Star Strider
am 4 Nov. 2015
.
1 Kommentar
Star Strider
am 4 Nov. 2015
The original (now deleted) post included this code:
Ginf = 4.0;
t = [0:500]
t1 = 100;
t2 = 500;
y1 = @(t) t/t1;
y2 = @(t) t/t2;
fun1 = @(y)exp(-y)./y;
Eiy1 = integral(@(t)fun1(y1(t)), 0, Inf);
Eiy2 = integral(@(t)fun1(y2(t)), 0, Inf);
E21(y1) = integral((Eiy1)./y, Inf, y1)
E21(y1) = integral((Eiy2)./y, Inf, y2)
G(t) = Ginf -[Eiy1*log(t/y1)-E21(y1)]+[Eiy2*log(t/y2)-E21(y2)]
plot(G(t), t)
Akzeptierte Antwort
Adam Barber
am 4 Nov. 2015
Your variables "y1" and "y2" are vectors. The command:
Eiy1 = integral(fun1, Inf, y1)
is really doing the integral of : exp(-y)/y from y = Inf to a vector.
This doesn't really make sense. The bounds (2nd and 3rd input arguments to integral) need to be scalar values.
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Operators and Elementary Operations finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!