If a number pops up again in a row.

How do I find the first number in a row that repeats itself and what position it was. For example, say I have a row x=[0 20 60 40 50 10 30 20] the first number to repeat itself is 20 and its the second number in the row so I would like my answer to be 2. Or take take something like y=[5 8 4 2 3 3 3] the first number to repeat its self is 3 and it does so as the 5th number so I would like the answer to be 5. Is there a general way to find the position of the first repeated number in a 1 row vector. Thank you.

Answer 1

[the cyclist]

I think this will do what you want:

y = [0 20 60 40 50 10 30 20];
% y = [5 8 4 2 3 3 3];

[u,i,j] = unique(y,'stable');

c = histcounts(j,[i; Inf]);

position = find(c>1,1);
value = u(position);

value is the first repeated value, and position is the position of its first occurrence.

Answer 2

[Star Strider]

This works:

x=[0 20 60 40 50 10 30 20];
y=[5 8 4 2 3 3 3];

[Ux,xa,xc] = unique(x,'stable');                        % Unique Numbers
fr_x = accumarray(xc,1);                                % Frequencies
Result_x = [Ux(fr_x>1), xa(fr_x>1)]                     % Number & Position In Vector

[Uy,ya,yc] = unique(y,'stable');                        % Same, But For ‘y’
fr_y = accumarray(yc,1);
Result_y = [Uy(fr_y>1), xa(fr_y>1)]

Result_x =
    20     2

Result_y =
     3     5