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What am I doing wrong in my code? Trying to detect if array has NaN.

2 Ansichten (letzte 30 Tage)
Tin Nguyen
Tin Nguyen am 14 Okt. 2015
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
So this is my code:
x = [ NaN NaN 24 ]
if isnan(x)==1
So I have this code. What I want it to do is to see if there are any NaN's in the vector. If there is an NaN then we make A be 2. If there isn't then A is just the the minimum number of x which is essentially 24.
But when I execute the program it keeps saying A=24 when it should be NaN. Any help would be greaty appreciated.

Antworten (1)

Rick Rosson
Rick Rosson am 14 Okt. 2015
if any(isnan(x))

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