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What am I doing wrong in my code? Trying to detect if array has NaN.

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So this is my code:
x = [ NaN NaN 24 ]
if isnan(x)==1
A=2
else
A=min(x)
end
So I have this code. What I want it to do is to see if there are any NaN's in the vector. If there is an NaN then we make A be 2. If there isn't then A is just the the minimum number of x which is essentially 24.
But when I execute the program it keeps saying A=24 when it should be NaN. Any help would be greaty appreciated.

Answers (1)

Rick Rosson
Rick Rosson on 14 Oct 2015
if any(isnan(x))

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