If I have a vector x = (1 ,3 ,4 -2, 5 ,6 8, 9, -4, -2)
I want to create a vector with the running average such that
y[n]=1/3{x[n-1]+x[n]+x[n+1]}
Thanks.

Antworten (1)

Guillaume
Guillaume am 8 Okt. 2015

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x = [1 ,3 ,4 -2, 5 ,6 8, 9, -4, -2]; %Please use valid notation in your question
y = conv(x, [1 1 1]/3, 'same')

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am 8 Okt. 2015

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am 8 Okt. 2015

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