making a running average
Ältere Kommentare anzeigen
If I have a vector x = (1 ,3 ,4 -2, 5 ,6 8, 9, -4, -2)
I want to create a vector with the running average such that
y[n]=1/3{x[n-1]+x[n]+x[n+1]}
Thanks.
Antworten (1)
Guillaume
am 8 Okt. 2015
x = [1 ,3 ,4 -2, 5 ,6 8, 9, -4, -2]; %Please use valid notation in your question
y = conv(x, [1 1 1]/3, 'same')
Kategorien
Mehr zu Interpolation finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!