misbehave of find function

Within a certain row of adjacent (1,0 matrix) one of it point known(as is also 1), I use it as base and looking the next one as long has 1, if not, I have to start from the initial column within that row. Unfortunately not behaving as expected. Any suggestion is welcome. Thanks all, see the input (adjacency matrix, code and output of the behaving find function:

Input file:

CON=[0  1  0  0  0  0  0  0  0  0  0  0  0  0  0  1
1  0  1  0  0  0  0  0  0  0  0  0  0  0  0  0
0  1  0  1  0  0  0  0  0  0  0  0  0  0  0  0
0  0  1  0  1  0  0  0  0  0  0  0  1  0  1  0
0  0  0  1  0  1  0  0  0  0  0  0  0  0  1  0
0  0  0  0  1  0  1  0  0  0  0  0  0  1  0  0
0  0  0  0  0  1  0  1  0  0  0  0  0  1  0  1
0  0  0  0  0  0  1  0  1  0  0  0  0  1  0  0
0  0  0  0  0  0  0  1  0  1  0  0  0  0  1  0
0  0  0  0  0  0  0  0  1  0  1  0  1  0  0  0
0  0  0  0  0  0  0  0  0  1  0  1  0  0  0  0
0  0  0  0  0  0  0  0  0  0  1  0  1  0  0  0
0  0  0  1  0  0  0  0  0  1  0  1  0  0  0  0
0  0  0  0  0  1  1  1  0  0  0  0  0  0  1  0
0  0  0  1  1  0  0  0  1  0  0  0  0  1  0  0
1  0  0  0  0  0  1  0  0  0  0  0  0  0  0  0
];

[r c]=size(CON);
for n=1:size(CON,1)
    [rr cc]=find(CON(:,n)>0,n,'last');nn=n,rr,
    [pp p]=find(CON(rr,cc+1:c)>0,1)
    if(p>=1)
      [rrc rcc]=find(CON(rr,cc+1:end)>0,1),
    else
     [rrc rcc]=find(CON(rr,1:cc-1)>0,1),
    end
end

OUTPUT of find function (eg nn=2, pp=1, p=1; I meanwhile expectes p to be 2)

nn =1 rr = 16 
pp =1 p =   6
rrc =1 rcc =6

nn =2 rr = 3
pp =1  p=  1
rrc =1 rcc =1

nn =3 rr =  4
pp =1 p =   2
rrc =1 rcc =2

nn =4 rr = 15
pp =1 p =1
rrc =1 rcc =1

nn =5 rr =15
pp =1 p =2
rrc =1 rcc =2

nn = 6 rr =14
pp =1 p =3
rrc =1 rcc =3

nn =7 rr =16
pp = 1 p =4
rrc =1 rcc = 4

nn = 8 rr =14
pp =1 p =5
rrc =1 rcc =5

nn = 9 rr =15
pp =3 p =3
rrc =3 rcc =3

nn =10 rr =13
pp =3 p = 3
rrc =3 rcc = 3

nn = 11 rr = 12
pp = 1 p =8
rrc =1 rcc =  8

nn =12 rr =13
pp = 2 p = 3
rrc =2 rcc =3

nn =13 rr = 12
pp =1 p =2
rrc =1 rcc =2

nn =14  rr =15
pp =4 p = 3
rrc =4 rcc =3

nn = 15 rr =14
pp =1 p = 2
rrc =1 rcc =2

nn =16  rr =7
pp = 1 p = 1
rrc = 1  rcc =1

[Star Strider]

You need to post your data (or sample data), what you want as output, and the relevant parts of your code.

Answer 1

[Eng. Fredius Magige]

I succeed to resolve my question, "misbehaving of find function" I used and incorporate flipdim function in find (... last)function; I was endup with all previous related numerical figures; I have noted that adjacency matrix is not enough exploration in solving engineering networking challenges. Thanks Matlab team.