To calculate value in a uitable

In a uitable table, I have produce a matrix as below:
>> a= [1 1 1 2 2 3 3 3 4 ; 3 3 1 4 4 4 3 1 1; 3 3 2 4 1 1 1 3 2]
a =
1 1 1 2 2 3 3 3 4
3 3 1 4 4 4 3 1 1
3 3 2 4 1 1 1 3 2
Therefore,in each row, I need to calculate the marks occur based on conditions below:
1. if no 3 occur in three cells continuously therefore the mark charged is 30.
2. if no 3 occur in two cells continuously and then followed by no 1 in the next cell, the mark charged is -20.
3. if no 3 occur in a cell and then followed by no 1 in the next cell, the mark charged is -10.
4. if no 3 occur in two cells continuously and then followed by no 2 in the next cell, the mark charged is -20.
5. if no 3 occur in a cell and then followed by no 2 in the next cell, the mark charged is 0.
Then, in each row, the total marks will calculate. Finally the result will be save in a matrix like this:
marks =
-30
-30
-20
This marks also will total to become an X value as below:
X = -80
How can I code this problem in matlab? Please help me and thank you.

 Akzeptierte Antwort

Andrei Bobrov
Andrei Bobrov am 21 Dez. 2011

0 Stimmen

try this code, I cant check now
s = size(a);
b = zeros(s);
b(abs(a - 3) < 1e3*eps) = -10;
k = [true(s(1),1) diff(a,1,2)~=0].*a;
p = arrayfun(@(x)10*nnz(strfind(k(x,:),[3 2])),(1:s(1))');
marks = sum(b,2) + p;

3 Kommentare

yue ishida
yue ishida am 21 Dez. 2011
Can you tell me how to find X? Thank you so much...
Andrei Bobrov
Andrei Bobrov am 21 Dez. 2011
Hi Yue!
X = sum(marks);
yue ishida
yue ishida am 21 Dez. 2011
Thanks..

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