Split 837 x 2 matrix into smaller n x 2 matrices

I have an 837 x 2 matrix with in the first column time, and in the second column some other values. I would like to split the matrix based on the difference between the time values in the first column.

For example: If you have this matrix:

A = [3 78; 6 52; 9 63; 300 123; 303 143; 306 107; 600 503]

I would like to split it between 9 and 300 and 306 and 600. So lets say if the difference in the first column is bigger than 50. So that i get those matrices out of it:

B = [3 78; 6 52; 9 63] C = [300 123; 303 143; 306 107] D = [600 503]

I already know how to calculate differences between them, now i only need to know how to split the matrices this way.

Thanks for the help!

Answer 1

[Matt J]

A = [3 78; 6 52; 9 63; 300 123; 303 143; 306 107; 600 503]

[m,n]=size(A); 

z=diff([0,find(diff(A(:,1))>50).',m]);

Acell=mat2cell(A,z,n);

    >> [B,C,D]=deal(Acell{:})

    B =

         3    78
         6    52
         9    63

    C =

       300   123
       303   143
       306   107

    D =

       600   503

[Royvg94]

Thanks!