Comparing values from structure to a scalar

for i=1:15
    A(i).A = [randi(10, 10, 1), rand(10,1)];
    for j=1:10
        mpc = loadcase('case14');

          results(i).A(j) = runpf(mpc);
      end
  end

Is there a way to add the following constraint in the for loop (the one with j=1:m):

if results(i).A.bus(:,8)>1.1
  A(i).A(j,2) = rand(10,1);
  results(i).A(j) = runpf(mpc);
end

I tried with that code above and it didn't work, those results were higher than 1.1 again.

Answer 1

[James Tursa]

Considering this line:

if results(i).A.bus(:,8)>1.1

It looks like a vector expression to me, which means it is equivalent to:

if all(results(i).A.bus(:,8)>1.1)

Was that your intention? Or was it your intention to take some action for each individual result > 1.1 ?

Also, this action doesn't look right:

A(i).A(j,2) = rand(10,1)

It looks like you are assigning a 10 x 1 column vector to a scalar element.

[Drazen Tubic]

well my intention is to change all those values in A(i).A that are causing results(i).A.bus(:,8) to be higher than 1.1. For example, in first iteration, A(1).A(1,2) is causing results(1).A(1).bus(:,8). In that case if any of the values from results(1).A(1).bus(:,8) is higher than 1.1, A(1).A(1,2) needs to be changed.

[Drazen Tubic]

And as for that assigning, i made a mistake, it should be equal to a random scalar: A(i).A(j,2) = rand(1)

[James Tursa]

Does this do what you want?

if any(results(i).A.bus(:,8)>1.1)

[Drazen Tubic]

unfortunately no, some results in results(i).A.bus(:,8) are still higher than 1.1 after i did that.