Initializing Array of Structures/Objects

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Sven
Sven am 5 Sep. 2015
Kommentiert: mary am 17 Nov. 2022
I simply want to set each struct in a struct-array. I set structarray to [] as it is an object property in my case, where it is being initialized as emtpy array. My first approach looks like:
structarray = [];
for i=1:10
structarray(i) = struct('index', i);
end
I get the following error: 'The following error occurred converting from struct to double: Error using double Conversion to double from struct is not possible.'
I can use an if else check and set the first element by:
structarray = struct('index', i);
Is there any easy way to write this straightforward similar to my code above?

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Geoff Hayes
Geoff Hayes am 5 Sep. 2015
Sven - why not use arrayfun to apply a function to each element in the array. In this case, your function would create a struct with a single field called index where its value is assigned its position/index within the array. The following should do what you require
myStructArray = arrayfun(@(x)struct('index',x),1:10)
Note how the first input to arrayfun is the function that creates the struct given an input parameter. The value of each parameter is determined from the second input to arrayfun - an array of indices from one to ten.
Try the above and see what happens!
  3 Kommentare
Bruno Luong
Bruno Luong am 17 Nov. 2022
myStructArray = arrayfun(@(i1,i2)struct('index1',i1,'index2',i2),zeros(1,10),zeros(1,10))
myStructArray = 1×10 struct array with fields:
index1 index2
mary
mary am 17 Nov. 2022
I found the answer:
myStructArray = arrayfun( @(x)struct('index1',x,'index2',x),zeros(1,10) )

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Walter Roberson
Walter Roberson am 6 Sep. 2015
structarray = struct('index', repmat({[]}, 1, 10));

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