Trying to create a program that asks user to input a number (integer) and then generates a list of randomly generated numbers (integers) between ‘1’ and number that user entered. Their should not be any repetition of numbers in the list.
I have this so far and I can't seem to figure out how to not repeat the #'s and to display the inputted integer. I know I have to use a if command but don't know how to execute! I have attempted to use if and else statements but I am stuck.
clc;
x = input('Enter a integer: ');
for x=1:x,
k=round(rand*x);
fprintf('%d\n',k)
end
Any Help is most appreciated.

1 Kommentar

Walter Diolosa
Walter Diolosa am 13 Dez. 2011
Output of script should look as follows when input is entered.
Enter and Integer: 10
ans=
5
1
10
2
4
8
3
6
7
9
Thanks

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 Akzeptierte Antwort

Wayne King
Wayne King am 13 Dez. 2011

0 Stimmen

x = input('Enter your number\n');
randperm(x)

6 Kommentare

Sean de Wolski
Sean de Wolski am 13 Dez. 2011
Faster fingers!
Walter Diolosa
Walter Diolosa am 13 Dez. 2011
Output of script should look as follows when input is entered.
Enter and Integer: 10
ans=
5
1
10
2
4
8
3
6
7
9
Wayne King
Wayne King am 13 Dez. 2011
you mean just
randperm(x)'
Wayne King
Wayne King am 13 Dez. 2011
you can just do
x = input('Enter your number\n');
randperm(x)'
Wayne King
Wayne King am 13 Dez. 2011
Walter, you should keep your posts in the thread. Why are you trying this?
x = input('Enter a integer: ');
for x=1:x,
k=randperm(x);
fprintf('%d\n',k)
end
Do not do for x=1:x, that is not what I showed you, read the help for randperm() it gives you a random permutation up to x
Walter Diolosa
Walter Diolosa am 13 Dez. 2011
Thanks!
Happy Holidays.

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Weitere Antworten (1)

Wayne King
Wayne King am 13 Dez. 2011

0 Stimmen

x = input('Enter a integer:\n');
y = randperm(x);
fprintf('%d\n',y);
Why are you trying to put it in to a for loop?

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