Why am I getting NaN using interp2?

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macdommy74
macdommy74 am 26 Aug. 2015
Kommentiert: macdommy74 am 26 Aug. 2015
  • I have a 450*90 matrix of values
  • I want to sample the matrix at 100 random sample points
However, while my interp2 function runs without errors, my output results vector contains NaN values after the 90th index.
The code below results in me getting NaN for points after the 90th index of vals - why, and how do I correct it?
Shouldn't I be able to sample 1 point from the matrix, or 50, or 100, or 1000 points?
Code:
row_vect = 1:450;
col_vect = 1:90;
[X,Y] = meshgrid(col_vect, row_vect);
V = abs(rand(450,90));
Xq = row_vect(1:100);
Yq = randi(89, 1,100);
vals = interp2(X, Y, V, Xq', Yq');
Thanks

Akzeptierte Antwort

Torsten
Torsten am 26 Aug. 2015
You try to extrapolate in Y-direction.
Read the description part for interp2 under
and you'll see why you get NaN for Y-values greater 90.
Best wishes
Torsten.
  3 Kommentare
Torsten
Torsten am 26 Aug. 2015
Use
[X,Y] = meshgrid(row_vect, col_vect);
instead of
[X,Y] = meshgrid(col_vect, row_vect);
Best wishes
Torsten.
macdommy74
macdommy74 am 26 Aug. 2015
I think this worked - thanks a million!!

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Weitere Antworten (1)

Walter Roberson
Walter Roberson am 26 Aug. 2015
Your problem is your X not your Y. max(X(:)) is 90 because your first argument to meshgrid() is col_vec which is 1:90
  1 Kommentar
macdommy74
macdommy74 am 26 Aug. 2015
I think this worked - thanks a million!!

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