How to smooth a plot?
len1 = [25, 250, 500, 750, 1000];
for k1 = 1:length(len1)
standard_deviation1(k1) = std(resdphs(1:5000, len1(k1)));
end
f10 = [110, 100, 90, 80, 70];
figure(3),plot(f10, standard_deviation1);xlabel('frequency'); ylabel('standarddev');
grid

2 Kommentare

Adam
Adam am 11 Aug. 2015
Your plot seems to bear no relation to the code that comes with it.
Mayank Lakhani
Mayank Lakhani am 11 Aug. 2015
Hey, Adam sorry for my mistake.

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

Star Strider
Star Strider am 11 Aug. 2015

1 Stimme

I’m not certain what you want to do, but you might consider experimenting with polyfit and its friends.

4 Kommentare

Mayank Lakhani
Mayank Lakhani am 11 Aug. 2015
I mean there shoud be no sharp edges in the curve, so it shoud be bending smoothly.
The polyfit function can do that, as can the interp1 function with one of the nonlinear method choices, such as 'spline', 'pchip' or 'cubic'.
If you want the curve defined at more points than you measured, also use the linspace function. For example, to get a vector of 100 points over the range of your ‘f10’ vector, consider creating ‘f10_interp’ (call it what you want) as:
f10_interp = linspace(min(f10), max(f10));
then to use it with interp1:
stdev1_interp = interp1(f10, standard_deviation1, f10_interp, 'spline');
and plot it as:
plot(f10_interp, stdev1_interp)
NOTE: Since I don’t have your data, this is UNTESTED CODE.
Experiment with it to get the result you want.
Mayank Lakhani
Mayank Lakhani am 12 Aug. 2015
Hey Star Strider, thanks it is working :)
Star Strider
Star Strider am 12 Aug. 2015
My pleasure!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Interpolation finden Sie in Hilfe-Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by