Piecewise Function Graphing Code Help

Hello all, I am trying to graph a piecewise function (shown with code below) and keep getting error saying "Error using piecewise (line 2) Not enough input arguments". I need an explanation as I am still learning MatLab. Thank you!

____________________________________________________________________________________________________________________________________

function y = piecewise(x)
  x1 = x(0<=x & x<1);
  y(find(0<=x & x<1)) = 2.1592*x1+2;
  x2=x(1<=x & x<2);
  y(find(1<=x & x<2)) = 1.0105*x2+1.1487;
  x3=x(2<=x & x<3);
  y(find(2<=x & x<3)) = 2.2635*x3-1.3573;
  x4=x(3<=x & x,4);
  y(find(3<=x & x,4)) = 3.7079*x4-5.6905;
  x5=x(4<=x & x<5);
  y(find(4<=x & x<5)) = 5.2649*x5-9.1411;
  x6=x(5<=x & x<6);
  y(find(5<=x & x<6)) = 6.8970*x6-20.079;
  plot(x, y)
  axis([-1 7 -25 25])
  grid on

[dpb]

Hmm...don't see a problem at the line 2 given that you call the function with an argument. Need to see the error in context with the line that called it causing the error.

[Jesse Rossman]

Everything that is shown I have given in the question. The whole script I copied and pasted, and the whole error that shows up I have copied and pasted. Might I be missing something above the function that should be included in the script? line 2 is "x1 = x(0<=x & x<1);" and I'm guessing that if something is wrong with this line then it might be wrong with the rest of the lines that are similar.....

[dpb]

"Everything that is shown I have given in the question."

Can't be... something had to invoke the function to get anything to happen....including the error message. That's what we've got to see.

[Jesse Rossman]

Ok. I may just not know what you need exactly because I'm new to Matlab. Here is a screen shot, does this help? Thanks for the help! I appreciate it.

[dpb]

Yep...the line you executed says only "piecewise" but the definition of the function is that it requires a vector x. Hence, quite rightly, Matlab complains that there aren't enough input arguments since zero arguments are fewer than one. :)

It appears that the function could have been written w/o needing an argument since the ranges internally are hardcoded, but that wasn't the way it was chosen to do it. Try

piecewise([0:0.1:6])

or, of course, define a vector and pass it...

x=[0:0.1:6];
piecewise(x)