How to find the day number of any year from a date?
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Md. Golam Mostafa
am 23 Jul. 2015
Bearbeitet: Sergey Kostrukov
am 12 Feb. 2022
I am very new in programming and therefore it is probably a novice's question. I have to write a script that takes a number of day(dd), month(mm) and year(yyyy)values arranged in three separate columns of a MATLAB variable and gives the day number of the year(e.g. for 03 March 2012, 31+29+3=63) as output.
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Peter Perkins
am 23 Jul. 2015
If you are using R2014b or later, the datetime data type allows you to compute the day of year using the day function:
>> x = [2012 1 2; 2012 3 3; 2013 3 3]
x =
2012 1 2
2012 3 3
2013 3 3
>> d = datetime(x)
d =
02-Jan-2012
03-Mar-2012
03-Mar-2013
>> day(d,'dayofyear')
ans =
2
63
62
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Peter Perkins
am 24 Jul. 2015
Presumably, you are not "using R2014b or later". datetime did not exist prior to that.
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Andrei Bobrov
am 24 Jul. 2015
x = [2012 1 2; 2012 3 3; 2013 3 3];
d = datenum(x);
out = d - datenum(year(d),1,1) + 1;
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Sergey Kostrukov
am 12 Feb. 2022
Bearbeitet: Sergey Kostrukov
am 12 Feb. 2022
Fractional value of days since biginning of the year (0-364.9999):
daysFrac = days(currentTime - datetime(year(currentTime), 1, 1, TimeZone=currentTime.TimeZone))
To get the whole number starting from 1 (i.e. day index):
floor(daysFrac + 1)
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